cement grinding ef bf bd ef bf bd

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  ABCD ∠ABC=60° E、FCD

  — ABCD ∠ABC=60° E、FCD、BC AE‖BD．EF⊥BC．DF=2 EF23

  EF BF BD Encoding EF BF BD EF BF BD

  — EF BF BD Unicode UTF 7 utf 7 4546204246204244 4991712706003223108 EF BF BD Unicode UTF 8 utf 8 4546204246204244 4991712706003223108 RGB16 ASCII GB2312

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  ABC AC=BC ∠ACB=90° BD∠ABC

  ABC ACB=90° AC=BC BDABCACD AEBDBDE ：BD=2AE ABC AC=BC ACB=90° DAC AE⊥BD BDE AE=½BD BDA

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  ∵DE⊥AC BF⊥AC Baidu Education

  — ：AE=CF A=C AD=BC ∴ ADE CBF（SAS） ：DFEBBFDE

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  ： ABC BD∠ABC EBD

  【】．【】（1） BD∠ABC∠ABD=∠CBD ABE CBD ∠AEB=∠CDB ∠ADE=∠AED

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  EF BB BF CSDN

  — 5 6。EF BB BFUnicodeBOM Byte Order Mark UTF8Zen Cart ie（） firefox。

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  ：EF∥BC EF= （BC AD）。 Baidu Education

  【】DF DFBCM∵AD∥BC∴∠ADM=∠DMC ∵FAC ∠MFC=∠AFD ∠ADM=∠DMC∴ ADF≅ MFC （ ∴DF=FMAD=MC ∵EBD

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  ：EF∥BC EF= （BC AD）。 Baidu Education

  【】DF DFBCM∵AD∥BC∴∠ADM=∠DMC ∵FAC ∠MFC=∠AFD ∠ADM=∠DMC∴ ADF≅ MFC （ ∴DF=FMAD=MC ∵EBD

  EF BF BD Encoding EF BF BD EF BF BD

  — EF BF BD Unicode UTF 7 utf 7 4546204246204244 4991712706003223108 EF BF BD Unicode UTF 8 utf 8 4546204246204244 4991712706003223108 RGB16 ASCII GB2312

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  byte[]String（EFBFBD3F） CSDN

  — 3 8。：byte[]String（split byte[]） UTF 8EFBFBDGBK3F：byte byte

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  【】 ABCD E F

  【】：（1） ∠B=∠D AB=CD ∠BAE=∠DCF ．（2）AECF AC⊥EF ．：：（1）∵

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  Serial UTF 8 EF BF BD MIT App Inventor Community

  — Hi there I m reading serial data using the serial component However from time to time characters are replace by a white question mark on a black diamond equivalent to hex "EF BF BD" I ve learned it s because of trying to interpret the values as text anything above 0x7F will be interpreter as a UTF 8 continuation byte and will fail to parse due to

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  ABC BC=AC ∠ACB=90° DAC AE⊥BD

  ABC BC=AC ∠ACB=90° DAC AE⊥BDBDE AE=BD ：BD∠ABC． 1

  ABC BD=CD BEADF AE=EF BE

  【】 ADG DG=AD BG ≌ BG=AC ∠CAD=∠G AE=EF ∠CAD=∠AFE ∠

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  UTF 8？？ CSDN

  — Replacement Character Unicode U FFFD UTF 8 EF BF BD WindowsUTF－8 BOM。 JavaUTF 8 BOM

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  ABCD AB=BD E FAB AD

  — ：①∵ABCD ∴AB=AD． ∵AB=BD ∴ ABD． ∴∠A=∠BDF=60°． ∵AE=DF AD=BD ∴ AED≌ DFB；②∵∠BGE=∠BDG ∠

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  FBD BC、ADE AB∥CD∥EF （1

  — （1）∵AB∥CD∥EF ∴ DFE∽ DBA BFE∽ BDC AEB∽ DEC ∴ DFE DBA BFE BDC AEB DEC 3；

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  Rt ABC ∠ACB=90° AC=BC DBC CE⊥AD

  — ∴ ACD≌ CBF．∴CD=BF． ∵CD=BD=1 2 BC ∴BF=BD ． ∴ BFD． ∵∠ACB=90° CA=CB ∴∠ABC=45°． ∵∠FBD=90° ∴∠ABF=45°． ∴∠ABC=∠ABF BA∠FBD． ∴BAFD BAFD

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  In the given figure it is given that AB = CF EF = BD and

  In the given figure it is given that AB = CF EF = BD and ∠ AFE =∠ DBC Then AFE is congruent to CBD by which criterion A SASB None of theseC ASAD SSS Login Study Materials NCERT Solutions [Adding BF on both the sides] AF = CB EF = BD [Given] ∠ A F E = ∠ D B C [Given] By SAS congruence criteria the two triangles are

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  8．ABCD E、F、G、HAB、BC

  8．ABCD E、F、G、HAB、BC、CD、DA AC=BD=2 ACBD 60° EFGH －4－20 MN MP PQ NQ MN ∥ 12 AC PQ ∥ 12 AC MP ∥ 12 BD NQ ∥ 12 BD MN ∥

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